fix(tui): handle LaTeX control spaces across line endings

packages/tui/CHANGELOG.md

@@ -15,6 +15,7 @@
 
 - Fixed fullscreen transcript search snapping back to the current match during manual scrolling and fragmented SGR mouse input leaking into the search query.
 - Fixed required LaTeX arguments starting on a new line being parsed as empty ([#7760](https://github.com/earendil-works/pi/issues/7760)).
+- Fixed LaTeX control spaces split across line endings causing complete expressions to fall back to raw source.
 
 ## [0.84.1] - 2026-08-07
 

packages/tui/src/latex.ts

@@ -920,6 +920,13 @@ class LatexParser {
 
 		let command = "";
 		const first = this.source[this.position] ?? "";
+		if (first === "\n" || first === "\r") {
+			this.position++;
+			if (first === "\r" && this.source[this.position] === "\n") {
+				this.position++;
+			}
+			return " ";
+		}
 		if (/[A-Za-z]/.test(first)) {
 			const start = this.position;
 			while (this.position < this.source.length && /[A-Za-z]/.test(this.source[this.position] ?? "")) {

packages/tui/test/latex.test.ts

@@ -415,6 +415,18 @@ R\left(\frac{\pi}{4}\right)
 		assert.strictEqual(renderLatex(String.raw`\det(A)`), "det(A)");
 	});
 
+	it("treats a backslash followed by a line ending as control space", () => {
+		const source = String.raw`\boxed{
+(1,1,1),\ (1,1,2),\ (1,2,5),\ (1,5,13),\ (2,5,29),\
+(1,13,34),\ (1,34,89)
+}.`;
+		assert.strictEqual(
+			renderLatex(source, { display: true }),
+			"[(1,1,1), (1,1,2), (1,2,5), (1,5,13), (2,5,29), (1,13,34), (1,34,89)].",
+		);
+		assert.strictEqual(renderLatex("a\\\r\nb"), "a b");
+	});
+
 	it("stacks operator limits in display mode", () => {
 		assert.strictEqual(renderLatex(String.raw`\sum_{i=0}^n x_i`, { display: true }), " n\n ∑  xᵢ\ni=0");
 		assert.strictEqual(renderLatex(String.raw`\min_{x\in X} f(x)`, { display: true }), "min f(x)\nx∈X");